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Naming Organic Compounds Explained | A Level Chemistry IUPAC Nomenclature Masterclass

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Tip: These are exact copies of the handwritten notes used in the video — includes slides, reaction summaries, diagrams, and rules for carboxylic acids and esters, perfect for revision and exam practice.

Naming Organic Compounds Explained | A Level Chemistry Organic Nomenclature Masterclass

Description:
Hello and welcome! In this A Level Chemistry masterclass, we explore naming organic compounds using IUPAC rules. Designed for Year 1 students, this video covers everything you need to confidently name organic molecules in exams and coursework.

You’ll learn how to:

Name compounds from displayed, structural, and skeletal formulas

Identify roots, prefixes, suffixes, and functional groups

Name alkanes, alkenes, alcohols, aldehydes, ketones, carboxylic acids, amines, nitriles, and halogenoalkanes

Handle branched chains, multiple functional groups, and functional group precedence

This video focuses on the most common functional groups for Year 1 Chemistry. Year 2 nomenclature, stereochemistry, and isomerism will be covered in upcoming videos.

By the end of this masterclass, you’ll be able to:

Identify the longest carbon chain in any molecule

Apply IUPAC naming rules to simple and complex organic compounds

Correctly place functional groups and branches in names

Name molecules containing multiple or competing functional groups

Timestamps:
0:00 Introduction
0:06 Overview of Nomenclature
0:56 IUPAC Naming Rules Explained
1:16 Structure of Names: Root, Suffix, Prefix
5:09 Alkanes and Simple Molecules
6:35 Alkenes and Numbering Double Bonds
9:51 Alkenes with Branches
14:36 Complex Branched Alkanes
24:20 Halogenoalkanes Naming
29:04 Alcohols Naming
32:02 Aldehydes and Ketones
34:49 Carboxylic Acids
36:28 Amines
37:53 Nitriles
41:12 Order of Precedence for Functional Groups
45:15 Multiple Functional Groups
48:36 Compounds with Two Identical Functional Groups

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Correction:
54:40 The functional group supposed to be CHO which is an aldehyde. so the answer would be 3-hydroxybutanal