DSA Python – Leetcode 19: Remove Nth Node from End of List | Two Pointer Approach – Part 63 [Hindi]
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🚀 Welcome to Part 63 of Code & Debug’s DSA in Python Course!
In this video, we solve Leetcode 19: Remove Nth Node from End of List, a popular Linked List problem that tests your understanding of two-pointer techniques and edge case handling.
📚 What you’ll learn in this video:
✅ Understanding the problem statement and constraints
✅ Two Pointer Approach (Fast and Slow pointers) for one-pass solution
✅ Time complexity: O(n), Space complexity: O(1)
✅ Step-by-step Python implementation with detailed dry run
✅ Handling edge cases like removing the head node or single-node lists
✅ Alternative solutions and comparison with other approaches
💡 Why is this problem important?
This problem is frequently asked in FAANG interviews as it tests your ability to manipulate pointers efficiently in linked lists. It also lays the foundation for solving advanced linked list problems like reversing nodes in groups, partitioning, and cycle detection.
👉 Link to solve this question:
https://leetcode.com/problems/remove-nth-node-from-end-of-list/description/
👉 Refer the article below for better understanding:
👉 📄 Access the full YouTube DSA Playlist Sheet (All Questions in Order):
🔗 https://docs.google.com/spreadsheets/d/1AWE15Fy3wD2iqu2vjK_R7cCiuvSsjYQclcdZmHpF66o/edit?usp=sharing
👉 Enroll in the free DSA Python course here:
https://codeanddebug.in/course/master-dsa-with-leetcode
👉 Enroll for Self-Paced Advance DSA course here:
https://codeanddebug.in/course/zero-to-hero-python-dsa
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